Geometry homework help

Geometry homework you can see through.

Use the marked facts to choose a theorem, find missing lengths and distinguish area from perimeter. Follow worked examples, proof reasoning and practice with explained answers.

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School geometry: marked diagrams, right triangles, similarity, angles and area.

Blue and white geometric pieces arranged as a tactile still life

See the idea in action

A right angle makes the relationship valid.

The right-angle condition is the starting point. Follow how the given legs determine the hypotenuse.

Geometry homework help · WORKED EXAMPLE

A right triangle has legs of 6 cm and 8 cm. Find the hypotenuse.

A right triangle with legs of 6 cm and 8 cmThe 6 cm vertical leg and 8 cm horizontal leg meet at a marked right angle. The opposite side is labeled c.
Use the marked right angle. The opposite side is the hypotenuse.
ANSWER10 cm

Prepared example for learning.

  1. 1

    Check the condition

    The triangle is right-angled, so the Pythagorean theorem applies.

  2. 2

    Label the longest side

    Let c be the hypotenuse, opposite the right angle.

  3. 3

    Use the relationship

    c² = 6² + 8² = 36 + 64 = 100.

  4. 4

    Interpret the root

    c = 10 cm. A side length is positive, and 10 is longer than either leg.

Try it in Lirno

Bring the diagram into the conversation.

Photograph the full figure in Lirno, including its labels and markings. Ask which fact makes the theorem apply before you calculate.

Start here

Read the marks. Choose the rule. Explain why.

  1. 01

    Read the markings

    List the lengths, angle labels, parallel lines, and equality marks provided.

  2. 02

    Choose a relationship

    Match the known facts to a theorem whose conditions are satisfied.

  3. 03

    Explain the conclusion

    Give the required units and describe why the result follows from the diagram.

Read the facts marked on the diagram

A printed triangle may not be drawn to scale. Use the stated lengths, angle values and conventional markings. A small square establishes a right angle; matching tick marks identify equal lengths. Parallel-line arrows supply a relationship that may justify an angle theorem. An angle that merely looks square is insufficient.

Separate given facts from conclusions. If a question asks you to prove two sides equal, their appearance cannot serve as the proof. When submitting a photo to Lirno, include the instruction and all markings so the explanation uses the same facts you have.

Find a hypotenuse or a missing leg

The Pythagorean theorem applies to a right triangle: a² + b² = c², with c opposite the right angle. For legs 6 cm and 8 cm, c² = 36 + 64 = 100, so c = 10 cm. A geometric length uses the positive root. The result should exceed either leg.

If the hypotenuse is 17 cm and one leg is 8 cm, the other leg b satisfies b² = 17² − 8² = 289 − 64 = 225. Thus b = 15 cm. Adding squares would be the wrong setup because 17 cm is already the hypotenuse. Label the sides before substituting.

Use triangle angles and straight-line angles

The interior angles of a triangle in ordinary plane geometry total 180°. If two are 48° and 67°, the third is 180° − 48° − 67° = 65°. Two adjacent angles that form a straight line also total 180°. An angle of 112° on that line leaves 68° for its adjacent partner.

Do not choose a rule from the numbers alone. Identify the triangle or straight line in the figure. When parallel lines are given, state which corresponding or alternate angles you are using. A written reason connects the angle calculation with the conditions that make it valid.

Match sides before using similarity

Similar triangles have equal corresponding angles and proportional corresponding side lengths. Suppose AB corresponds to DE, with AB = 4 cm and DE = 10 cm. The scale factor from the first triangle to the second is 10/4 = 2.5. If BC = 6 cm corresponds to EF, then EF = 6 × 2.5 = 15 cm.

Keep the direction of the ratio consistent. To return from the larger triangle to the smaller, divide by 2.5. Lengths scale by the factor, while areas scale by its square: a factor of 2.5 in corresponding lengths gives an area factor of 6.25. Rotation does not change which labeled parts correspond.

Distinguish area from perimeter

For a rectangle 7 cm long and 3 cm wide, area is 7 × 3 = 21 cm². Perimeter is 2(7 + 3) = 20 cm. Area measures the region; perimeter measures its boundary. The two answers can be numerically close while describing different quantities.

For a triangle, area is one half of base times perpendicular height. A base of 10 cm and perpendicular height of 4 cm gives 20 cm². A sloping side cannot replace the height unless it is perpendicular to that chosen base. An external altitude can still give the correct height.

Write a proof as connected statements

A proof needs a reason for each conclusion. For an isosceles triangle with two equal sides given, the angles opposite those sides are equal. If the remaining angle is 40°, the equal angles share the remaining 140°, giving 70° each. The equal-side condition justifies the equal-angle claim.

Ask Lirno to find the first unsupported statement in your proof rather than replace the whole proof. Check the theorem conditions, the correspondence of labels and the units of the final quantity. A useful explanation says why a relationship applies before carrying out its arithmetic.

Check whether the information determines one answer

Two side lengths alone do not determine a triangle. Sides of 6 cm and 8 cm give a hypotenuse of 10 cm only when the angle between them is stated to be 90°. If a third side c is unspecified, the triangle inequality requires 2 < c < 14 cm; it does not pick a single length. Read the right-angle mark before treating the example as a Pythagoras problem.

A uniqueness check can also help with area. A triangle with base 10 cm needs its perpendicular height to determine its area. A sloping side of 6 cm alone cannot be substituted as that height. If the figure appears to supply an answer but the labels do not, explain which additional fact you need rather than estimating from the picture.

Your next small win

Let the marked facts choose the method.

Before calculating, say which information makes your theorem apply. A sketch helps you organize the facts, but its appearance alone does not establish a right angle, equal sides or a particular scale.

Prepared mini exercise

A right triangle has perpendicular legs of 5 cm and 12 cm. What is the hypotenuse, and how can you check that your result is plausible?

Give me a hint

The right-angle condition lets you add the squares of the two legs. The hypotenuse is opposite the right angle and must be longer than either leg.

Show the reasoning

The squared hypotenuse is 5² + 12² = 25 + 144 = 169 cm². Its length is √169 = 13 cm. The result is greater than both 5 cm and 12 cm, as it should be.

Make it yours

Carry the idea into your own homework.

If 13 cm were the hypotenuse and 5 cm were one leg, you would subtract squares to find the missing leg. Explain that change before doing the calculation. Ask Lirno to check your setup against the marked diagram.

Adapt a question for Lirno →

Catch it before it trips you up

Three small details.
A stronger attempt.

Inspect the part of the method that this exercise actually tests. These are the three errors to check first.

01

Treating the picture as proof

A side that looks longer is not necessarily marked longer. Use labels, given statements and theorem conditions. Keep the original figure visible when you explain which facts you used.

02

Choosing the wrong side

The hypotenuse is opposite the right angle. Label that relationship first; adding two known squared lengths is only the right setup when those known lengths are the legs.

03

Stopping at a squared length

A sum of squares gives a squared length. Take the positive square root for the side length and use cm rather than cm² in the final answer.

Try a different case

Same idea.
A new decision.

Make an attempt before opening the explanation. These original tasks test a different part of the method, so a familiar answer alone will not be enough.

01

A missing leg is different from a hypotenuse

A right triangle has hypotenuse 13 cm and one leg 5 cm. Find the other leg.

Compare your reasoning

Let the missing leg be b. Since the 13 cm side is opposite the right angle, 5² + b² = 13².

Then b² = 169 − 25 = 144, so b = 12 cm. Use the positive root for a length. Check: 25 + 144 = 169, and 13 cm is the longest side.

Keep this clue: Adding the two given squares would treat the hypotenuse as a leg.

02

Length scale and area scale

Two similar rectangles have corresponding sides 4 cm and 12 cm. The smaller area is 20 cm². What is the larger area?

Compare your reasoning

The length scale factor is 12/4 = 3. Both length and width scale by 3.

Area therefore scales by 3 × 3 = 9, giving 20 × 9 = 180 cm². Multiplying the area by 3 alone would give 60 cm² and miss the second dimension.

Keep this clue: Use k for lengths and k² for areas of similar plane figures.

One-minute understanding checkSimilar figures have a length scale factor of 2. What is their area scale factor?

Read the explanation

Length and width both scale by 2, giving an area factor of 4.

Prepared question · Your choice stays in this page.

Ask a better question

A prompt you
can make your own.

Paste this into Lirno with your assignment. Add your attempt and say where you need help.

This is a right triangle with legs 6 cm and 8 cm. Explain why I add the squares, and give me a similar problem to try without showing its answer first.

Quick quality check

Make every geometric claim traceable.

  • The diagram information is given or proved
  • The theorem conditions are satisfied
  • Corresponding sides and angles are matched
  • The answer has the correct units and scale

FAQs

Questions about Geometry

When do I add or subtract squares in Pythagoras?

Add the squared legs to find the squared hypotenuse. To find a missing leg, subtract the squared known leg from the squared hypotenuse. Both require an established right triangle. Take the positive root for a length.

Can I measure the printed diagram?

Only if the task explicitly asks for measurement. Otherwise use the given lengths and markings because the picture may not be drawn to scale.

Does doubling side length double area?

For similar figures, a length scale factor of 2 gives an area scale factor of 4. Area scales by the square of the length factor.

Which height do I use for triangle area?

Use the perpendicular distance from the chosen base line to the opposite vertex. A sloping side is not automatically the height; the perpendicular may lie outside the triangle.

Check the foundations

Sources & further reading

The examples on this page are original teaching exercises. These resources explain the underlying concepts.

Published by Rocket Digital Limited for HomeworkPath. How these guides are prepared →

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